[tex]dane:\\v_{o} = 0\\m = 600 \ g = 0,6 \ kg\\h = 0,8 \ m\\g = 10\frac{m}{s^{2}}\\szukane:\\E_{k}=?\\\\Rozwiazanie\\\\Z \ zasady \ zachowania \ energii\\\\E_{k} = E_{p} = mgh\\\\E_{k} = mgh\\\\E_{k} =0,6 kg\cdot10\frac{m}{s^{2}}\cdot0,8 \ m\\\\E_{k} = 4,8 \ J[/tex]
Odp. Energia kinetyczna doniczki Ek = 4,8 J.
