Odpowiedź:
1.
a) CH₃COOH <=> CH₃COO⁻+ H⁺
HCOOK --> HCOO⁻ + K⁺
b) HCOOH <=> HCOO⁻ + H⁺
(CH₃COO)₂Ba ---> 2CH₃COO⁻+ Ba²⁺
c) C₂H₅COOH <=> C₂H₅COO⁻ + H⁺
C₂H₅COOK --> C₂H₅COO⁻ + K⁺
2.
a) 2HCOOH + O2 --> 2CO2 + 2H2O.
b) CH3COOH + O2---->2CO + 2H2O
3.
a) 6CH₃COOH + 2 Al -----> 2 (CH₃COO)₃Al + 3 H₂
6CH₃COOH + Al₂O₃ -----> 2 (CH₃COO)₃Al + 3 H₂O
3CH₃COOH + Al(OH)₃ ----> (CH₃COO)₃Al + 3 H₂O
b) palmitynian sodu:
C₁₅H₃₁COOH + NaOH --> C₁₅H₃₁COONa + H₂O
stearynian sodu:
C₁₇H₃₅COOH + NaOH --> C₁₇H₃₅COONa + H₂O
oleinian sodu:
C₁₇H₃₃COOH + NaOH --> C₁₇H₃₃COONa + H₂O
Myślę że jest git
