[tex]a)\\\\bok\ trojkata:\ a=8\\\\wysokosc\ trojkata\ rownobocznego :\\\\h=\frac{a\sqrt{3}}{2}=\frac{\not{8}^4\sqrt{3}}{\not{2}^1}=4\sqrt{3}\\\\pole\ trojkata\ rownobocznego:\\\\P=\frac{a^2\sqrt{3}}{4} =\frac{8^2\sqrt{3}}{4} =\frac{64\sqrt{3}}{4}=16\sqrt{3}\ [j^2][/tex]
[tex]b)\\\\bok\ trojkata:\ a=9\\\\wysokosc\ trojkata\ rownobocznego :\\\\h=\frac{a\sqrt{3}}{2}=\frac{9\sqrt{3}}{2} \\\\pole\ trojkata\ rownobocznego:\\\\P=\frac{a^2\sqrt{3}}{4} =\frac{9^2\sqrt{3}}{4} =\frac{81\sqrt{3}}{4 }\ [j^2][/tex]
