Odpowiedź:
a) [tex]N_{2} + 3H_{2} -> 2 NH_{3}[/tex]
b) [tex]2 CO + O_{2} -> 2 CO_{2}[/tex]
c) [tex]3 Fe_{3}O_{4} + 8Al -> 4 Al_{2}O_{3} + 9 Fe[/tex]
d) [tex]2 Na + 2 HCl -> 2 NaCl + H_{2}[/tex]
e) [tex]P_{4}O_{10} + 6 H_{2}O -> 4 H_{3}PO_{4}[/tex]
f) [tex]4 NH_{3} + 5 O_{2} -> 4 NO + 6 H_{2}O[/tex]
Reakcje wymiany: c, d, f
