Odpowiedź:
1. brakuje danych (potrzebna jest temperatura do obliczenia)
2. Q=mL + cm(T2-T1)
m=3 kg
L = 333,7 kJ/kg =333700 J/kg
c= 4200 J/kgK
T2-T1=100-0 = 100 C = 100 K
Q = 3*333700 + 4200*3*100 = 226100 J = 226,1 kJ
3.m1 = 100 kg
m2 = 40 kg
T1=20 C
T2=80 C
T3 = ?
ΔT1 = T3-T1
ΔT2 = T2-T3
Q1 = Q2
m1cΔT1 = m2cΔT2
m1ΔT1=m2ΔT2
m1T3 -m1T1 = m2T2-m2T3
m2T2 + m1T1 = (m1+m2)T3
T3 = (m2T2 + m1T1)/(m1+m2)= (40*80 + 100*20)/(140) = 37 C
4. Q1 = Q2
m1c1ΔT1 = m2c2ΔT2
0,2*4200*(60-20) / (0,1*(100-60)) = c2
c2 = 8400 J/kgK
