[tex]0 = - 7x + 3 + 2 {x}^{2} [/tex]
[tex]2 {x}^{2} - 7x + 3 = 0[/tex]
liczymy deltę (trójkąt)
[tex]delta = 49 - 4 \times 2 \times 3 = 49 - 24 = 25[/tex]
[tex] \sqrt{delta} = \sqrt{25} = 5[/tex]
[tex] x_{1} = \frac{7 - 5}{4} = \frac{2}{4} = \frac{1}{2} [/tex]
[tex] x_{2} = \frac{7 + 5}{4} = \frac{12}{4} = 3[/tex]
zatem odp.: x€{1/2, 3}
