POMÓŻCIE !
a) 5^6 * 5^3 * 5^7 =?
b) 3* 3^12 * 3 =?
c) 17^5 * 17^18 : 17^21=?
d) 11^5 : 11^5 * 11^3=?
e) 5^8 * ( 5^7 : 5^2) =?
f) 34^16 : ( 34^5 * 34)=?
g) 12^6 * 12^7 / 12^9=?
h) ( 1/2)^13 * (1/2)^3 / (1/2)^14=?


Odpowiedź :

Odpowiedź:

[tex]a)\ \ 5^6*5^3*5^7=5^{6+3+7}=5^{16}\\\\\\b)\ \ 3*3^{12}*3=3^{1+12+1}=3^{14}\\\\\\c)\ \ 17^5*17^{18}:17^{21}=17^{5+18-21}=17^2\\\\\\d)\ \ 11^5:11^5*11^3=1*11^3=11^3\\\\\\e)\ \ 5^8*(5^7:5^2)=5^8*(5^{7-2})=5^8*5^5=5^{8+5}=5^{13}\\\\\\f)\ \ 34^{16}:(34^5*34)=34^{16}:34^6=34^{16-6}=34^{10}\\\\\\g)\ \ \dfrac{12^6*12^7}{12^9}=\dfrac{12^{6+7}}{12^9}=\dfrac{12^1^3}{12^9}=12^{13-9}=12^4[/tex]

[tex]h)\ \ \dfrac{(\frac{1}{2})^1^3*(\frac{1}{2})^3}{(\frac{1}{2})^1^4}=\dfrac{(\frac{1}{2})^{13+3}}{(\frac{1}{2})^1^4}=\dfrac{(\frac{1}{2})^{16}}{(\frac{1}{2})^{14}}=(\frac{1}{2})^{16-14}=(\frac{1}{2})^2=\frac{1}{4}[/tex]