Odpowiedź:
a)[tex]CH_{3}[/tex]-[tex]CH_{2}[/tex]-[tex]CH_{2}[/tex]-[tex]CH_{2}[/tex]-[tex]CH_{3}[/tex]+[tex]Cl_{2}[/tex]→[tex]CH_{3}-CH_{}-CH_{2}-CH_{2}-CH_{3}\\\\[/tex] + HCl
Ι
Cl
b) [tex]CH_{3}-CH_{2}-CH_{2}-CH_{2}-CH_{2}-CH_{2}-CH_{3}[/tex] +[tex]Br_{2}[/tex] →[tex]CH_{3}-CH_{2}-CH_{}-CH_{2}-CH_{2}-CH_{2}-CH_{3}[/tex] + HBr
I
Br