[tex]a)\\(-\frac{1}{5})^{3} = (-\frac{1}{5})\cdot(-\frac{1}{5})\cdot(-\frac{1}{5}) = -\frac{1}{125}\\\\b)\\(0,01)^{2} = 0,0001\\\\c)\\(-17)^{0} = 1\\\\d)\\(\frac{1}{2})^{4}-(\frac{1}{3})^{2} = \frac{1}{16}-\frac{1}{9} = \frac{9}{144} - \frac{16}{144} = -\frac{7}{144}[/tex]
[tex]e)\\(-0,1)^{4}\cdot20^{3}-(-2)^{4} =0,0001\cdot8000-16 = 0,8 -16 = -15,2\\\\f)\\(1\frac{1}{3})^{3}\cdot(-3\frac{3}{4})^{2}:3 - (\frac{1}{3})^{2} = (\frac{4}{3})^{3}\cdot(-\frac{15}{4})^{2}:3 - \frac{1}{9} = \frac{64}{27}\cdot\frac{225}{16}\cdot\frac{1}{3}-\frac{1}{9} =\\\\=\frac{4}{9}\cdot25 -\frac{1}{9} = \frac{100}{9}-\frac{1}{9} =\frac{99}{9} = 11[/tex]
