Odpowiedź:
A
[tex]\sqrt{5^2 * 11^2 * 2^2} = \sqrt{(5 * 11 * 2)^2} = 5 * 11 * 2 = 10 * 11 = 110[/tex]
B Zaktualizowane
[tex]\sqrt{\frac{3^2}{4^2} } * \sqrt{\frac{4}{8\\1}} = \sqrt{(\frac{3}{4})^2} * \sqrt{\frac{2^2}{9^2}} = \frac{3}{4} * \sqrt{(\frac{2}{9})^2} = \frac{3}{4} * \frac{2}{9} = \frac{1}{6}[/tex]
C
[tex]\sqrt{16 +9} = \sqrt{25} = \sqrt{5^2} = 5[/tex]
D
[tex]\sqrt{8} * \sqrt{18} = \sqrt{2^3} * \sqrt{3^2 * 2} = \sqrt{2^4 * 3^2} = \sqrt{4^2 * 3^2} = \sqrt{12^2} = 12[/tex]
E
[tex]\sqrt{169-144} = \sqrt{25} = \sqrt{5^2} = 5[/tex]
F
[tex]\sqrt{\frac{2^3}{5}} * \sqrt{\frac{5^3}{2}} = \sqrt{\frac{2^2}{5^2}} = \sqrt{(\frac{2}{5})^2} = \frac{2}{5}[/tex]
Szczegółowe wyjaśnienie:
