Odpowiedź:
4)
[tex] \frac{18x - 6}{3} + (2x - 1) \times 3 = \frac{3(6x - 2)}{3} + 6x - 3 = 6x - 2 + 6x - 3 = 12x - 5[/tex]
5)
[tex](12 {x}^{2} - 3) \div 3 - 4x(2x - 2) = \frac{3(4 {x}^{2} - 1)}{3} - 8 {x}^{2} + 8x = 4 {x}^{2} - 1 - {8x}^{2} + 8x = - 4 {x}^{2} + 8x - 1[/tex]
