Odpowiedź:
Zad 4
e) x/4 = x+3/2
2x = 4x + 12
2x - 4x = 12
-2x = 12 | : (-2)
x = -6
f) 5/x+3 = 1,5/x
5/x+3 = 4/x-2, x [tex]\neq[/tex] -3, x = [tex]\neq[/tex] 2
5 (x - 2) = 4 (x + 3)
5x - 10 = 4x + 12
5x - 4x = 12 + 10
x = 22, x [tex]\neq[/tex] -3, x = [tex]\neq[/tex] 2
g) 2m-4/3 = 3m/4
4 (2m - 4) = 9m
8m - 16 = 9m
8m - 9m = 16
-m = 16 | : (-1)
m = -16
Zad 5
d) 4x + 5/-4 = 4 - 3x/-2
- 4x + 5/4 = - 4 - 3x/2
4x + 5/4 = 4 - 3x/2
2(4x + 5) = 4 (4 - 3x)
8x + 10 = 16 - 12x
8x + 12x = 16 - 10
20x = 6 | : 20
x = 3/10
e) 3/-2x+7 = 9/5-3x
3/-2x +7 = 9/5-3x, x [tex]\neq[/tex] 7/2, x [tex]\neq[/tex] 5/3
3 (5 - 3x) = 9( -2x + 7)
15 - 9x = -18x + 63
-9x + 18x = 63 - 15
9x = 48 | : 9
x = 16/3, x [tex]\neq[/tex] 7/2, x [tex]\neq[/tex] 5/3
x = 16/3
x = 5 i 1/3
f) 2x/4x - 3 = 1 i 1/2x/3x - 7
2x/4x-3 = 1 i 1/2 * x/3x - 7, x [tex]\neq[/tex] 3/4, x [tex]\neq[/tex] 7/3
2x/4x - 3 = 3/2x/3x-7
2x/4x-3 = 3x/2/3x-7
2x/4x - 3 = 3x/2(3x - 7)
4x * (3x - 7) = 3x * (4x - 3)
12[tex]x^{2}[/tex] - 28x = 12[tex]x^{2}[/tex] - 9x
-28x = -9x
-28x + 9x = 0
-19x = 0
x = 0 , x [tex]\neq[/tex] 3/4, x [tex]\neq[/tex] 7/3
x = 0
Szczegółowe wyjaśnienie:
