Zadanie
I - równoległobok
a = 4
h = 6
P = a · h
P = 4 · 6 = 24
II - trapez
a = 5
b = 3
h = 6
[tex]P=\frac{(a+b)\cdot h}{2}\\\\P=\frac{(5+3)\cdot6}{2}=8\cdot3=24[/tex]
III - równoległobok
a = 4
h = 5
P = a · h
P = 4 · 5 = 20
IV - romb
d₁ = 8
d₂ = 6
[tex]P=\frac{d_{1}\cdot d_{2} }{2}\\\\P=\frac{8\cdot6}{2}=\frac{48}{2} =24[/tex]
