Odpowiedź:
a)
Z tw. pitagorasa
8² + 6² = x²
64 + 36 = x²
100 = x²
√100 = x
10 = x
b)
y² = 17²- 15²
y² = 289 - 225
y² = 64
y = √64
y = 8
c)
2² + 6² = z²
4 + 36 = z²
40 = z²
√40 = z
2√10 = z
d)
a² = (3√2)² - 4²
a² = (9*2) - 16
a² = 18 - 16
a² = 2
a = √2
e)
(3√3)² + (2√5)² = b²
(9*3) + (4*5) = b²
27 + 20 = b²
47 = b²
√47 = b
f)
c² = √13² - 3²
c² = 13 - 9
c² = 4
c = √4
c = 2
