pomocy podane wielkości przedstaw w hercach
a.47\s=
b.1944\24min=
c.2160\4m=


Odpowiedź :

a.47\1s=47Hz

b.1944\24min=1944/(24*60s) = 1944/1440s = 97/72 Hz ≈ 1,35 Hz

c.2160\4min = 2160/(4*60s) = 2160/240s = 9 Hz