Odpowiedź:
[tex]4x^2-9=0\\\\4x^2=9\ \ /:4\\\\x^2=\frac{9}{4}\\\\x=\sqrt{\frac{9}{4}}\ \ \ \ \vee\ \ x=-\sqrt{\frac{9}{4}}\\\\x=\frac{3}{2}\ \ \ \ \ \ \vee\ \ \ \ x=-\frac{3}{2}\\\\\\\\4x^2=12x-9\\\\4x^2-12x+9=0\\\\(2x-3)^2=0\\\\2x-3=0\\\\2x=3\ \ /:2\\\\x=\frac{3}{2}\\\\x=1\frac{1}{2}[/tex]
