Odpowiedź:
[tex]f)\\\\\frac{2}{5}(3-x)=-2\\\\\frac{6}{5}-\frac{2}{5}x=-2\ \ /*5\\\\6-2x=-10\\\\-2x=-10-6\\\\-2x=-16\ \ /:(-2)\\\\x=8\\\\\\g)\\\\\frac{3}{4}(2-3x)=-6\\\\\frac{6}{4}-\frac{9}{4}x=-6\ \ /*4\\\\6-9x=-24\\\\-9x=-24-6\\\\-9x=-30\ \ /:(-9)\\\\x=\frac{30}{9}\\\\x=3\frac{3}{9}\\\\x=3\frac{1}{3}[/tex]
[tex]h)\\\\\frac{1}{5}(x-3)=9-x\\\\\frac{1}{5}x-\frac{3}{5}=9-x\ \ /*5\\\\x-3=45-5x\\\\x+5x=45+3\\\\6x=48\ \ /:6\\\\x=8\\\\\\i)\\\\\frac{0,6+x}{2}=x+1\ \ /*2\\\\0,6+x=2x+2\\\\x-2x=2-0,6\\\\-x=1,4\ \/*(-1)\\\\x=-1,4[/tex]
