[tex]dane:\\r = 40 \ cm = 0,4 \ m\\m = 3 \ kg\\n = 10\\t = 2 \ min = 2\cdot60 \ s = 120 \ s\\szukane:\\a) \ T, f = ?\\b) \ v = ?\\c) \ F_{d} = ?\\\\Rozwiazanie\\\\a)\\T = \frac{t}{n} = \frac{120 \ s}{10} = 12 \ s\\\\f = \frac{!}{T} = \frac{1}{12 \ s}\approx0,083 \ Hz\\\\b)\\v = \frac{2\pi r}{T}=\frac{2\cdot3,14\cdot0,4 \ m}{12 \ s} \approx0,21\frac{m}{s}\\\\c)\\F_{d} = \frac{mv^{2}}{r} = \frac{3 \ kg\cdot(0,21\frac{m}{s})^{2}}{0,4 \ m}\approx0,33 \ N[/tex]
