zad 34 str 261 pls potrzebuje juz dam naj​

Zad 34 Str 261 Pls Potrzebuje Juz Dam Naj class=

Odpowiedź :

a. [tex]\sqrt{\sqrt{400} :5 } = \sqrt{20:5} = \sqrt{4} = 2[/tex]

b. [tex]\sqrt{\sqrt{36}+\sqrt{100} } = \sqrt{6+10} = \sqrt{16 }= 4[/tex]

c. [tex]\sqrt[3]{25\sqrt{25} } = \sqrt[3]{25*5} = \sqrt[3]{125} = 5[/tex]

d.[tex]\sqrt{\sqrt{8\sqrt[3]{2\sqrt[3]{64}}}} = \sqrt{8\sqrt[3]{2*4}} = \sqrt{8\sqrt[3]{8}} = \sqrt{8*2} = \sqrt{16} = 4[/tex]