Odpowiedź:
[tex]p = d*g*h[/tex]
[tex]d = 997 \frac{kg}{m^{3}}[/tex]
[tex]g = 9.8 \frac{m}{s^{2}}[/tex]
[tex]h_{a} = 0.1m\\h_{b} = 1700m\\h_{c} = 11000m[/tex]
[tex]1kPa = 1000Pa[/tex]
[tex]a)\\p = 997 \frac{kg}{m^{3}} * 9.8\frac{m}{s^{2}} * 0.1m = 977,06 Pa = 0.99706 kPa[/tex]
[tex]b)\\p = 997 \frac{kg}{m^{3}} * 9.8\frac{m}{s^{2}} * 1700m = 16 610 020 Pa = 16610,02 kPa[/tex]
[tex]c)\\p = 997 \frac{kg}{m^{3}} * 9.8\frac{m}{s^{2}} * 11000m = 107 476 600 Pa = 107476,6 kPa[/tex]
