A = {4, 6, 8, 9} i B = {1, 4, 9}
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A ∪ B = {4, 6, 8, 9} ∪ {1, 4, 9} = {1, 4, 6, 8, 9}
A ∩ B = {4, 6, 8, 9} ∩ {1, 4, 9} = {4, 9}
(A ∪ B) \ (A ∩ B) = {1, 4, 6, 8, 9} \ {4, 9} = {1, 6, 8}
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A \ B = {4, 6, 8, 9} \ {1, 4, 9} = {6, 8}
B \ A = {1, 4, 9} \ {4, 6, 8, 9} = {1}
(A \ B) ∪ (B \ A) = {6, 8} ∪ {1} = {1, 6, 8}
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(A ∪ B) \ (A ∩ B) = {1, 6, 8}
(A \ B) ∪ (B \ A) = {1, 6, 8}
Zatem: (A ∪ B) \ (A ∩ B) = (A \ B) ∪ (B \ A)
Odp. Podana w treści zadania równość zachodzi.