Odpowiedź:
[tex]5-\sqrt{27}x\leq \frac{5\sqrt{12}}{6}x-\frac{1}{3}\ \ /*6\\\\30-6\sqrt{27}x\leq 5\sqrt{12}x-2\\\\-6\sqrt{27}x-5\sqrt{12}x\leq -2-30\\\\-6\sqrt{9*3}x-5\sqrt{4*3}x\leq -32\\\\-6*3\sqrt{3}x-5*2\sqrt{3}x\leq -3\\\\-18\sqrt{3}x-10\sqrt{3}x\leq -32\\\\-28\sqrt{3}x \leq -32\ \ /:(-4)\\\\7\sqrt{3}x\geq 8\ \ /:(7\sqrt{3})\\\\x\geq \frac{8}{7\sqrt{3}}*\frac{\sqrt{3}}{\sqrt{3}}\\\\x\geq \frac{8\sqrt{3}}{7*3}\\\\x\geq \frac{8\sqrt{3}}{21}[/tex]
