Odpowiedź:
-(3c-2)(c-1)-c(c-2)= (-3c²+2c)(c-1)-c(c-2)= -3c²+3c+2c-2-c(c-2)= -3c²+3c+2c-2-c²+2c= -4c²+7c-2
2(3a²-1)-(a+2)(a+2)= 6a²-2-(²+4a+4)= 6a²-2-a²-4a-4= 5a²-4a-6
5x²(x²+1)-(x²-2)(x²+3)= 5x⁴+5x²-(x⁴+3x²-2x²-6)= 5x⁴+5x²-x⁴-3x²+2x²+6= 4x⁴+4x²+6
