[tex]ogolna \ postac \ prostej : \\ \\Ax+By+c =0 \\ \\ 3x + 4y = 8 \\\\3x+4y-8=0,\ \ \ \ A(1,-2)\\ \\wzor \ na \ odleglosc \ punktu\ A(x_{o},y_{o}) \ od \ prostej:\\ \\d=\frac{|Ax_{o}+By_{o}+C|}{\sqrt{A^2 + B^2}}\\\\d=\frac{|3*1 + 4*(-2)+ (-8) |}{\sqrt{ 3^2 +4^2}} =\frac{|3 -8 -8|}{\sqrt{ 9+16}}=\frac{|-13|}{\sqrt{ 25}}=\frac{13}{5}=2,6[/tex]
