Odpowiedź :
Obliczenia :
[tex]a=2, \ b=4, \ m=28, \ n=56\\\\a^m\cdot b^n=2^{28}\cdot4^{56}=2^{28}\cdot(2^2)^{56}=2^{28}\cdot2^{2\cdot56}=\\\\=2^{28}\cdot2^{112}=2^{140}=(2^2)^{70}=\boxed{4^{70}}[/tex]
[tex]dla \ \ a = 2, \ b = 4, \ m = 28, \ n = 56\\\\a^{m}\cdot b^{n} = 2^{28}\cdot4^{56} = (2^{2})^{14} \cdot4^{56} = 4^{14}\cdot4^{56} = 4^{14+56} = 4^{70}\\\\Odp. \ C.[/tex]