Odpowiedź:
zad 1
a)
P = (- 3 , - 1 ) , Q = ( 3 , 2 )
xp = - 3 , xq = 3 , yp = - 1 , yq = 2
a -współczynnik kierunkowy prostej = (yq - yp)/(xq - xp) = (2 + 1)/(3 + 3) =
= 3/6 = 1/3
b)
P = ( - 3 , 4 ) , Q = ( 3 , 2 )
xp = - 3 , xq = 3 , yp = 4 , yq = 2
a = (yq - yp)/(xq - xp) = (2 - 4)/(3 + 3) = - 2/6 = - 1/3
c)
P = (- 3 , - 2 ) , Q = ( 1 , 4 )
xp = - 3 , xq = 1 , yp = - 2 , yq = 4
a = (yq - yp)/(xq - xp) = (4 + 2)/(1 + 3) = 6/4 = 3/2 = 1 1/2