DANE
h=35
x:y=4:9
OBLICZ
a,b,c
Trojkat ACD jest podobny do CDB-->
x:h=h:y--->h²=xy
x/y=4/9--->x=4/9y podstawiam do w/w
h²=4/9y² pierwiastkuje
h=2/3y--->y=3/2h
x=4/9*3/2h=2/3h
c=x+y=(2/3+3/2)h
c=(4/6+9/6)h=13/6h
Z tw Pit i CDB
a²=h²+y²---->a=√(h²+9/4h²)=h√(13/4)=h/2√13
Z tw Pit i ACD / ew z calego trojkata/
b₂=h²+x₂---->b=√(h₂+4/9h²)=h√(13/9)=h/3√13
ODP
a=35/2√13
b=35/3√13
c=13/6*35
pozdrawiam
