a) log2 64 =
b) log3 81 =
c) logx 16 = 2
d) log3 x = 3
e) log2 3 + log2 (16/3) =
f) log3 2 + log2 (4,5) =
g) log4 81 - log3 (20,25) =
h) log2 48 - log2 6 =


Odpowiedź :

a) log2 64 = log₂2⁶=6
b) log3 81 =log₃3⁴=4
c) logx 16 = 2
x²=16
x=4
d) log3 x = 3
3³=x
x=27
e) log2 3 + log2 (16/3) =log₂(3*16/3)=log₂16=log₂2⁴=4
f) log3 2 + log2 (4,5) =log₃2+log₃(9/2)/log₃2=log₃2+(log₃9-log₃2)/log₃2=
log₃2 + log₃9/log₃2 - log₃2/log₃2=log₃2+2/log₃2
g) log4 81 - log3 (20,25) = log4 81 - log3 (81/4) =log4 3⁴ - log3 3⁴+log3 4 =
4log4 3 - 4+ 1/log4 3
h) log2 48 - log2 6 =log2 48/6=log2 8=log2 2³=3