Oblicz :

a) [7^0-(8/27)^(1/3) ]^(-2)=

b) 3^2+[∜(3^5 )∙(1/3)^(-3/4) ]=

c)[〖17〗^(-5)+(1/4)^(7/3) ]^0=

d) (3^(-1)-(3/2)^(-3))/(16/81)^(3/4) ∙(3^2-5^0 )=

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