Odpowiedź :
((x-y)²-(x+y)²)÷2x²=
((x²-2xy+y²)-(x²+2xy+y²)÷2x²=
(x²-2xy+y²-x²-2xy-y²)÷2x²=
-4xy÷2x²=-2xy÷x²=-2 y/x(ułamek)
((x²-2xy+y²)-(x²+2xy+y²)÷2x²=
(x²-2xy+y²-x²-2xy-y²)÷2x²=
-4xy÷2x²=-2xy÷x²=-2 y/x(ułamek)
((x²-2xy+y²)-(x²+2xy+y²))÷2x²=(x²-2xy+y²-x²-2xy-y²)÷2x²=-4xy÷2x²=-2xy÷x²=-2x⁻¹y