g(x)=-x²+3.
a=-1 b=0 c=3 = > a<0 parabola ramionami w dol
Δ= 0²-4·(-1)·3=0+12=12
√Δ=√12=√(2²·3)=2√3
x₁= (0-2√3) / (2·(-1)) = ( -2√3) / (-2) = -√3
x₂ = (0+2√3) / (2·(-1)) = ( 2√3) / (-2) =√3
p = 0/(2·(-1)) = 0/(-2) = 0
q= (-12)/(4·(-1)) = (-12)/(-4)= 3
W(p,q)
W(0,3)
