Odpowiedź :
3x²>8x+3
3x²-8x-3>0
3x²-8x-3=0
a=3 b=-8 c=-3
Δ=b²-4ac= (-8)²-4*3*(-3)
Δ=64+36=100
√Δ=10
x1=-b-√Δ/2a=8-10/2*3=-2/6=-1/3
x2==-b+√Δ/2a=8+10/6=18/6=3
3x²-8x-3>0
3x²-8x-3=0
a=3 b=-8 c=-3
Δ=b²-4ac= (-8)²-4*3*(-3)
Δ=64+36=100
√Δ=10
x1=-b-√Δ/2a=8-10/2*3=-2/6=-1/3
x2==-b+√Δ/2a=8+10/6=18/6=3
3x² > 8x + 3
3x² - 8x - 3 > 0
Δ = b² - 4ac
Δ = (-8)² - 4 * 3 * (-3) = 64 +36 = 100
√Δ = 10
x₁ = -b / 2a
x₁= 8 -10/2*3 = -2/6 = -⅓
x₂ = 8 + 10/2*3 = 18/6 =3
x∈ (-∞; -⅓) U (3; +∞)
3x² - 8x - 3 > 0
Δ = b² - 4ac
Δ = (-8)² - 4 * 3 * (-3) = 64 +36 = 100
√Δ = 10
x₁ = -b / 2a
x₁= 8 -10/2*3 = -2/6 = -⅓
x₂ = 8 + 10/2*3 = 18/6 =3
x∈ (-∞; -⅓) U (3; +∞)