Odpowiedź :
(x+7)²+(2x-5)²-(x-3)(x+3)= x²+7²+2x²-5²-x²-3x-3x-9=
=3x²+2²-6x-9
3 razy (-⅓)² + (2)² - 6 razy (-⅓) - 9=
=⅓ + 4 + 2 - 9 = 6⅓ - 9 = I wpisujesz wynik :)
=3x²+2²-6x-9
3 razy (-⅓)² + (2)² - 6 razy (-⅓) - 9=
=⅓ + 4 + 2 - 9 = 6⅓ - 9 = I wpisujesz wynik :)
(x+7)²+(2x-5)²-(x-3)(x+3)= dla x =-⅓
(-⅓+7)²+(2(-⅓)-5)²-(-⅓-3)(-⅓+3) =
=(6⅔)²+(-5⅔)²-(-3⅓)×2⅔=
=44⁴/₉+32¹/₉ +7⁷/₉=83¹²/₉ = 84⅓
(-⅓+7)²+(2(-⅓)-5)²-(-⅓-3)(-⅓+3) =
=(6⅔)²+(-5⅔)²-(-3⅓)×2⅔=
=44⁴/₉+32¹/₉ +7⁷/₉=83¹²/₉ = 84⅓