stosując poznane prawa działań na potęgach oblicz:
(3¹⁰ ×(¹\₂₇)³)²
------------------=
9


(5-3 ×(⅖)⁰)⁻²=


((-1⅓)⁻³)×(⁴\₃)⁴=


Odpowiedź :

(3¹⁰ ×(¹\₂₇)³)² (3²⁰ * (¹/₂₇)⁶)
a) ------------------= -----------------=
9 3²
(3²⁰ * (1/27)⁶): 3²= (3¹⁴ * (3*1/27)⁶):3²=(3⁸*(3*1/9)⁶): 3²= (3² * (3*1/3)⁶):3²= (3²* 1⁶):3²= 1

b)(5-3 ×(⅖)⁰)⁻²=(5-3*1)⁻²= (2)⁻²= ¼

c)((-1⅓)⁻³)×(⁴\₃)⁴= (-4/3)⁻³ * (4/3)⁴= (3/4)³ * (4/3)⁴= (¾ * ⁴/₃)³ * ⁴/₃ = 1 * ⁴/₃=⁴/₃