Odpowiedź :
1)
m C2H5OH= 46g
m 9H2O= 162g
48g alkoholu--------208groztworu
xg alkoholu---------100g roztworu
22.11g alkoholu
x = 22,11%
2)
Cp=3%
mr=80g
ms=Cp*mr/100%
ms=3*80/100
ms = 2,4g jodu
zad.1
M(C2H5OH)=2*12g+6*1g+16g=46g
M(H2O)=2*1g+16g=18g
ms=46g
mr=46g+9*18g=208g
Cp=?
Cp=ms/mr * 100%
Cp=46g/208g * 100%
Cp=22,1%
zad.2
mr=80g
Cp=3%
ms=?
Cp=ms/mr * 100% /*mr
Cp*mr=ms*100% /:100%
ms=Cp*mr/100%
ms=3%*80g/100%
ms=2,4g