a) 2x – 7 - [3 - 2x - 2(1-2x)] = x - 1] – 11
b) 10 – [2(1-x) - 3(2x + 5)] = 2(x + 5)+1
c) 8 - 3x - 2[4 - (x + 5)] = 3(x + 1) - 1
d 1 - 2x - 3[2x-(-5+x)] = x + 4


Odpowiedź :

a) 2x-7-3+2x+2-2x=x-1-11
2x-8=x-12
x=-4

b)10-2+2x+6x+15=2x+10+1
8x+23=2x+11
6x=-12
x=-0.5

c)8-3x-8+2x+10=3x+3-1
-x+10=3x+2
-4x=-8
x=2

d)1-2x-6x-15+3x=x+4
-5x-14=x+4
-6x=18
x=-3