rozwiąż
a -6,2:3,1-(-2,1×10)
b 2×[3,25-(-3,75)]×3,5
c 3×(-10)+(-27)
d(-9)×(-8)-5×(-100)
e (-2,7-3:10)³×(-1)
f (-0,2)×(-100)-4½×⅔


Odpowiedź :

a -6,2:3,1-(-2,1×10)=
=-2+21=19

b 2×[3,25-(-3,75)]×3,5=
= 2×[3,25+3,75)]×3,5=
=2×[7]×3,5=
=14×3,5=49

c 3×(-10)+(-27)=
=-30-27=
=-57

d(-9)×(-8)-5×(-100)=
=72+500=572

e (-2,7-3:10)³×(-1)=
=(-2,7-0,3)³×(-1)=
=(-3)³×(-1)=
=-3×(-1)=3

f (-0,2)×(-100)-4½×⅔ =
=20-9/2×2/3=
=20-3=17