(√2-1)³=(√2)³ - 3 * (√2)² * 1 + 3 * √2 * 1² - 1³ = 2√2 - 3 * 2 + 3√2 - 1 = 5√2 - 6 - 1 = 5√2 - 7
[tex]\\(\sqrt2-1)^3=(\sqrt2)^3-3(\sqrt2)^2+3*\sqrt2-1= \\2\sqrt2-6+3\sqrt2-1=-7+5\sqrt2 \\wzor \\(a-b)^3=a^3-3a^2b+3ab^2-b^3[/tex]
