Ze średniej harmonicznej:
[tex]v_{sr} = \frac{2}{\frac{1}{6} + \frac{1}{14}} = \frac{2}{\frac{14}{84} + \frac{6}{84}} = \frac{2}{\frac{20}{84}} = \frac{2 \cdot 84}{20} = 8,4 [\frac{km}{h} ] [/tex]
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
