Odpowiedź:
[tex]a)\ \ \dfrac{5^3*5^8}{5^1^1:5^2}=\dfrac{5^{3+8}}{5^{11-2}}=\dfrac{5^1^1}{5^9}=5^{11-9}=5^2=25\\\\\\b)\ \ \dfrac{(\frac{3}{7})^1^0*(\frac{14}{3})^1^0}{(2^3)^3}=\dfrac{(\frac{\not3^1}{\not7_{1}}*\frac{\not14^2}{\not3_{1}})^1^0}{2^9}=\dfrac{2^1^0}{2^9}=2^{10-9}=2^1=2\\\\\\c)\ \ \dfrac{0,25^3:0,5^3}{5^3}=\dfrac{(0,25:0,5)^3}{5^3}=\dfrac{0,5^3}{5^3}=(0,5:5)^3=0,1^3=0,001[/tex]
[tex]d)\ \ (\frac{1}{3})^{-1}*(\frac{1}{3})^{-2}=(\frac{1}{3})^{-1-2}=(\frac{1}{3})^{-3}=3^3=27\\\\\\e)\ \ (\frac{2}{5})^{-3}:(-\frac{2}{5})^{-2}=(\frac{2}{5})^{-3}:(\frac{2}{5})^{-2}=(\frac{2}{5})^{-3-(-2)}=(\frac{2}{5})^{-3+2}=(\frac{2}{5})^{-1}=\\\\=(\frac{5}{2})^1=\frac{5}{2}=2\frac{1}{2}\\\\\\f)\ \ ((0,2)^{-1})^{-3}=(0,2)^3=(\frac{1}{5})^3=\frac{1}{125}[/tex]
