[tex]5\frac{3}{4}-\frac{3}{4}\cdot(4\frac{2}{5}-\frac{34}{10})-2\frac{3}{8}+(3\frac{1}{4}-1\frac{2}{3})=5\frac{3}{4}-\frac{3}{4}\cdot(\frac{22}{5}-\frac{17}{5})-2\frac{3}{8}+(3\frac{3}{12}-1\frac{8}{12})=\\\\=5\frac{3}{4}-\frac{3}{4}\cdot\frac{5}{5}-2\frac{3}{8}+(2\frac{15}{12}-1\frac{8}{12})=5\frac{3}{4}-\frac{3}{4}\cdot1-2\frac{3}{8}+1\frac{7}{12}=5\frac{3}{4}-\frac{3}{4}-2\frac{3}{8}+1\frac{7}{12}=[/tex][tex]=5-2\frac{3}{8}+1\frac{7}{12}=6\frac{7}{12}-2\frac{3}{8}=6\frac{14}{24}-2\frac{9}{24}=4\frac{5}{24}\\\\\\2\frac{5}{8}+6-(3\frac{1}{3}-1\frac{3}{4})+(7-3\frac{7}{12})=2\frac{5}{8}+6-(3\frac{4}{12}-1\frac{9}{12})+(6\frac{12}{12}-3\frac{7}{12})=\\\\=2\frac{5}{8}+6-(2\frac{16}{12}-1\frac{9}{12})+3\frac{5}{12}=2\frac{5}{8}+6-1\frac{7}{12}+3\frac{5}{12}=\frac{21}{8}+6-\frac{19}{12}+\frac{41}{12}=[/tex]
[tex]=\frac{21}{8}+6+\frac{22}{12}=\frac{63}{24}+\frac{144}{24}+\frac{44}{24}=\frac{251}{24}=10\frac{11}{24}[/tex]
Kolejność wykonywania działań
- działania w nawiasach
- mnożenie
- dodawanie lub odejmowanie w kolejności od strony lewej do prawej
