[tex]f(x)=-4x^2+x+5\\g(x)=-4x+6\\\\f(x) > g(x)\\\\-4x^2+x+5 > -4x+6\\-4x^2+x+4x+5-6 > 0\\-4x^2+5x-1 > 0\\\\\Delta=5^2-4*(-4)*(-1)=25-16=9\\\sqrt{\Delta}=3\\\\x_1=\frac{-5-3}{-8}=1\\x_2=\fraC{-5+3}{-8}=\frac14\\\\a < 0 - \text{ramiona skierowane w dol}\\\\f(x) > g(x) \text{ dla } x\in(\frac14; 1)[/tex]
