Zad. 1
o - ojciec
s - syn
[tex]\left \{ {o+s=50} \atop {o-5=3(s-5)}} \right. \\\left \{ {{o=50-s} \atop {50-s-5=3s-15}} \right. \\\left \{ {{o=50-s} \atop {-s-3s=-15-45}} \right. \\\left \{ {{o=50-s} \atop {-4s=-60 /:(-4)}} \right. \\\left \{ {{o=35} \atop {s=15}} \right.[/tex]
Odp. Ojciec ma 35 lat a syn 15.
Zad. 2
c - ciocia
b - basia
[tex]c=3b\\b+16=c-6\\\left \{ {{c=3b} \atop {b+16=c-6}} \right. \\\left \{ {{c=3b} \atop {b+16=3b-6}} \right. \\\left \{ {{c=3b} \atop {b-3b=-6-16}} \right. \\\left \{ {{c=3b} \atop {-2b=-22 /:(-2)}} \right. \\\left \{ {{c=33} \atop {b=11}} \right.[/tex]
Odp. Ciocia ma 33 lata a Basia 11.
