Odpowiedź:
Masa tego ciała m = 400 kg.
Obliczenia:
[tex]Dane:\\F = 40 \ N\\v_{o} = 10\frac{m}{s}\\t = 60 \ s\\v = 4\frac{m}{s}\\Szukane:\\m = ?\\\\Rozwiazanie\\\\Z \ II \ zasady \ dynamiki \ Newtona\\\\a = \frac{F}{m} \ \ |\cdot m\\\\a\cdot m = F \ \ |:a\\\\\underline{m = \frac{F}{a}}\\\\a = \frac{\Delta v}{t} = \frac{v_{o}-v}{t} = \frac{(10-4)\frac{m}{s}}{60 \ s} = \frac{6\frac{m}{s}}{60 \ s} = \underline{0,1\frac{m}{s^{2}}}[/tex]
[tex]m = \frac{40 \ N}{0,1\frac{m}{s^{2}}} = \frac{40 \ kg\cdot\frac{m}{s^{2}}}{0,1\frac{m}{s^{2}}}\\\\\boxed{m = 400 \ kg}[/tex]
