4x^4 - 13x^2 + 3 = 0
x^2 = t, gdzie t >= 0
4t^2 - 13t + 3 = 0
delta(t) = 169 - 48 = 121
p(delta(t)) = p(121) = 11
t1 = (13+11)/8 = 24/8 = 3
t2 = (13-11)/8 = 2/8 = 1/4
oba naleza do dziedziny t, wiec:
x^2 = 3 V x^2 = 1/4
x = p(3) V x = -p(3) V x = 1/2 V x = -1/2
