Odpowiedź:
[tex]a)\ \ \dfrac{5}{\sqrt{6}}=\dfrac{5}{\sqrt{6}}\cdot\dfrac{\sqrt{6}}{\sqrt{6}}=\dfrac{5\sqrt{6}}{\sqrt{6}\cdot\sqrt{6}}=\dfrac{5\sqrt{6}}{6}\\\\\\b)\ \ \dfrac{7}{\sqrt{14}}=\dfrac{7}{\sqrt{14}}\cdot\dfrac{\sqrt{14}}{\sqrt{14}}=\dfrac{7\sqrt{14}}{\sqrt{14}\cdot\sqrt{14}}=\dfrac{\not7^1\sqrt{14}}{\not14_{2}}=\dfrac{\sqrt{14}}{2}[/tex]
[tex]c)\ \ \dfrac{30}{\sqrt{5}}=\dfrac{30}{\sqrt{5}}\cdot\dfrac{\sqrt{5}}{\sqrt{5}}=\dfrac{30\sqrt{5}}{\sqrt{5}\cdot\sqrt{5}}=\dfrac{\not30^6\sqrt{5}}{\not5_{1}}=6\sqrt{5}\\\\\\d)\ \ \dfrac{6}{5\sqrt{6}}=\dfrac{6}{5\sqrt{6}}\cdot\dfrac{\sqrt{6}}{\sqrt{6}}=\dfrac{6\sqrt{6}}{5\sqrt{6}\cdot\sqrt{6}}=\dfrac{6\sqrt{6}}{5\cdot6}=\dfrac{\not6^1\sqrt{6}}{\not30_{5}}=\dfrac{\sqrt{6}}{5}[/tex]
