Odpowiedź:
[tex]\dfrac{8\cdot4\frac{1}{4}-11\frac{1}{5}:9\frac{1}{3}-(-2\frac{1}{3}):\frac{5}{3}}{14:2\frac{2}{9}+8\frac{2}{5}:1\frac{2}{7}}=\dfrac{\not8^2\cdot\frac{17}{\not4_{1}}-\frac{56}{5}:\frac{28}{3}+2\frac{1}{3}:\frac{5}{3}}{14:\frac{20}{9}+\frac{42}{5}:\frac{9}{7}}=\dfrac{34-\frac{\not56^2}{5}\cdot\frac{3}{\not28_{1}}+\frac{7}{\not3_{1}}\cdot\frac{\not3^1}{5}}{\not14^7\cdot\frac{9}{\not20_{10}}+\frac{\not42^1^4}{5}\cdot\frac{7}{\not9_{3}}}=[/tex]
[tex]=\dfrac{34-\frac{6}{5}+\frac{7}{5}}{\frac{63}{10}+\frac{98}{15}}=\dfrac{34+\frac{1}{5}}{\frac{189}{30}+\frac{196}{30}}=\dfrac{34\frac{1}{5}}{\frac{385}{30}}=\dfrac{\frac{171}{5}}{\frac{77}{6}}=\frac{171}{5}:\frac{77}{6}=\frac{171}{5}\cdot\frac{6}{77}=\frac{1026}{385}=2\frac{256}{385}[/tex]
