Odpowiedź:
[tex]4,6+3\frac{2}{5}=4\frac{6}{10}+3\frac{2}{5}=4\frac{3}{5}+3\frac{2}{5}=7\frac{5}{8}=8\\\\7,5+3\frac{3}{4}=7\frac{5}{10}+3\frac{3}{4}=7\frac{1}{2}+3\frac{3}{4}=7\frac{2}{4}+3\frac{3}{4}=10\frac{5}{4}=11\frac{1}{4}[/tex]
[tex]4\frac{1}{3}-2,7=4\frac{1}{3}-2\frac{7}{10}=4\frac{10}{30}-2\frac{21}{30}=3\frac{40}{30}-2\frac{21}{30}=1\frac{19}{30}\\\\4\frac{2}{7}-3,9=4\frac{2}{7}-3\frac{9}{10}=4\frac{20}{70}-3\frac{63}{70}=3\frac{90}{70}-3\frac{63}{70}=\frac{27}{70}[/tex]
[tex]\frac{2}{5}\cdot1,9=\frac{\not2^1}{5}\cdot\frac{19}{\not10_{5}}=\frac{1}{5}\cdot\frac{19}{5}=\frac{19}{25}\\\\1\frac{1}{2}\cdot0,6=\frac{3}{2}\cdot\frac{6}{10}=\frac{3}{2}\cdot\frac{3}{5}=\frac{9}{10}[/tex]
