Odpowiedź:
[tex]1)\\\\\dfrac{2^1^1:(2^6\cdot2^2)}{2^2}=\dfrac{2^1^1:2^{6+2}}{2^2}=\dfrac{2^1^1:2^8}{2^2}=\dfrac{2^{11-8}}{2^2}=\dfrac{2^3}{2^2}=2^{3-2}=2^1=2\\\\\\2)\\\\A.\ \ (2^9)^8=2^{9\cdot8}=2^{72}\\\\B.\ \ ((-3)^7)^7=(-3)^{7\cdot7}=(-3)^{49}\\\\C.\ \ ((-0,1)^6)^9=((0,1)^6)^9=0,1^{6\cdot9}=0,1^{54}\\\\D.\ \ ((10^5)^8)^2=10^{5\cdot8\cdot2}=10^{80}[/tex]
