Odpowiedź:
[tex]a)\ \ w(x)=x^6-4x^4=x^4(x^2-4)=x^4(x-2)(x+2)\\\\b)\ \ w(x)=4x^4+8x^3+4x^2=4x^2(x^2+2x+1)=4x^2(x+1)^2\\\\\\x^2+2x+1\ \ zastosowalam\ \ wz\'or\ \ skr\'oconego\ \ mno\.zenia\\\\a^2+2ab+b^2=(a+b)^2\\\\x^2+2x+1=x^2+2\cdot x\cdot1+1^2[/tex]
